Is there a way to query the user id given a certain user display name? What about the other way around? The display name can be changed any time, so the id seem to be the better solution to identify an account. Is it possible to link to the user page by id? (Something like https://www.openstreetmap.org/user?id=xxxx) asked 22 Nov '11, 15:22  bastik |
5 Answers:
You can't link by id (as Gnonthgol says), but if you want to find an id from a given display name, go to that user's edits page, select a changeset from the list, then view the Changeset XML to find the uid. answered 22 Nov '11, 16:10  EdLoach ♦ |
Do bear in mind that user names can change. If you want to do a search (by current or by historical name or by ID) you can use http://whosthat.osmz.ru . answered 03 Jun '14, 19:00  SomeoneElse ♦ |
The API has supported a call with the UID as argument for quite a while now. The call returns user information including the user name: https://www.openstreetmap.org/api/0.6/user/the_uid This will naturally only give you the current mapping uid->user name and not historic ones. answered 03 Jun '14, 14:47  SimonPoole ♦ edited 03 Jun '14, 15:17 Can't open the link? (27 Jun '15, 01:37) marla729 Marla729 Try this :- https://www.openstreetmap.org/user/marla729 (27 Jun '15, 07:05) BCNorwich Link Simon gave returns "Couldn't find a file/directory/API operation by that name". Link BCNorwich gave is just the normal profile link. (08 May '20, 21:06) Richlv You are slightly, that is 5 years, late :-) (08 May '20, 21:27) SimonPoole ♦ |
Since this has been nudged to the top of the list again, I might as well explain how I've always done it :)
answered 08 May '20, 23:59 SomeoneElse ♦ |
Yes an UID is better. On Odbl here, they might as well have cumulated the merits for the same UID !!! answered 14 Sep '12, 20:45  GentilPapou 1 This doesn't seem to answer the question, though (and the website is gone by now). (08 May '20, 21:07) Richlv |
Is there anything new on that topic. Is it still impossible to get a user name from its uid?
See new answer from me below.