How can I get the location I want if there are two locations with same name?

Question

I am searching for a map of sub-districts (admin level 6) within a district(admin level 5) in which each sub-dist will be clickable on my webpage. The problem is there are some districts with one of its sub-district having same name as the district itself. when I search for the district I get the sub-district instead.

Sub District with same name alt text

What i want alt text

[out:json];

{{geocodeArea: chittoor, Andhra Pradesh, india}}->.searchArea;

(

  relation["type"="boundary"][admin_level = 6](area.searchArea);

);
out;

(
    relation[admin_level = 6];
);
out skel;

Here i am trying to use output of one set as input for next set? How can i archive this?

Answer 1

1

I think you cant rely on geocodeArea for this type of operation. Instead you will need an unambiguous search string using standard overpass syntax (for instance possibly based on the wikidata item) and convert that to an area using the overpass statement which can then be assigned to the .searchArea set, something like area[wikidata="Q11103437"]->.searchArea;. (Of course if you know the object's OSM Id you can access the area by adding a magic number to the id).

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answered 06 Dec '20, 18:55

SK53 ♦
28.1k●48●268●433
accept rate: 22%

I am doing something like that in python, but geocode return list (geo_result VARIABLE) of location matching the district name so both the sub-district and district are returned. How can i select the right one?

geolocator = Nominatim(user_agent="city_compare") geo_results = geolocator.geocode(dist_name, exactly_one=False)

Searching for relation in result set

for r in geo_results: #print(r.address, r.raw.get("osm_type")) if r.raw.get("osm_type") == "relation" and r.raw.get('type')=='administrative': city = r break # Calculating area id area_id = int(city.raw.get("osm_id")) + 3600000000 #print(area_id) # Excecuting overpass call query2 = """ [out:json]; area({})->.searchArea;

       (
           relation["type"="boundary"][admin_level = 6](area.searchArea);
        );
      out geom;""".format(area_id)
   url = 'https://overpass-api.de/api/interpreter'
   r= requests.get(url, params={'data': query2})

(06 Dec '20, 19:10) PramodG

Ah, my approach gets round this Nominatim issue in Overpass, but does not resolve the actual Nominatim issue.

(07 Dec '20, 13:03) SK53 ♦

It will probably work to use the place_rank in the Nominatim results. If it doesn't, query Nominatim or Overpass-API for the details of each candidate (at which point you will have the admin_level tag).

(07 Dec '20, 21:47) maxerickson

How can I get the location I want if there are two locations with same name?

Searching for relation in result set

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