Hello everyone, the query below works. I would have liked to optimize it so as to accelerate the result. Can you help me ? Thank you in advance. Mathieu
http://overpass.mydevicexxx.com/api/interpreter?data=[out:json][timeout:25];(node(around:1000,48.84203354,2.790979589)["name"~"."]["amenity"="parking"]->.b;node(around:1000,48.84203354,2.790979589)["name"~"."]["amenity"="school"]->.c;node(around:500,48.84203354,2.790979589)["name"~"."]["amenity"="townhall"]->.d;way(around:500,48.84203354,2.790979589)["name"~"."]["amenity"="townhall"]->.d;relation(around:500,48.84203354,2.790979589)["name"~"."]["amenity"="townhall"]->.d;node(around:500,48.84203354,2.790979589)["name"~"."]["railway"="subway_entrance"]->.f;node(around:500,48.84203354,2.790979589)["name"~"."]["railway"="tram_stop"]->.g;node(around:1000,48.84203354,2.790979589)["name"~"."]["tourism"="museum"]->.h;node(around:500,48.84203354,2.790979589)["name"~"."]["highway"="bus_stop"]->.j;node(around:500,48.84203354,2.790979589)["name"~"."]["leisure"="park"]->.k;way(around:500,48.84203354,2.790979589)["name"~"."]["leisure"="park"]->.k;relation(around:500,48.84203354,2.790979589)["name"~"."]["leisure"="park"]->.k;);.b out qt tags 1;>;.c out qt tags 1;>;.d out qt tags 1;>;.f out qt tags 1;>;.g out qt tags 1;>;.h out qt tags 1;>;.j out qt tags 1;>;.k out qt tags 1;
asked 01 Aug '17, 18:24
mdk83
25●2●2●4
accept rate: 0%
edited 02 Aug '17, 07:41
scai ♦
33.3k●21●309●459
You can already simplify your query a bit by using "
|" in queries, which acts like "a or b" -> "a|b", and "~" (tilde) instead of "=". For example:["amenity"~"parking|school"]-- Not sure how much that will speed up the process though and what your desired result should look like.