Hi, I want to export a map of a certain area from OpenStreetMaps and I would like to know the dimensions (in meters) of the area I am exporting. OpenStreetMaps allows me to manually select the area I want (Export button on top left of the screen) and it provides me with its pixel size, scale and lon/lat coordinates. Is it possible to translate those data into a meter dimensions? That is to say, obtain map size in format such as, for instance, 234x500m. Should I use any other tool different from directly exporting from the web? Are the dimensions available through osm data or another different format? I am sorry if this question is too stupid but I have not been able to work it out in my own. asked 23 May '16, 09:20 Fa__ |
You could get very rough dimensions by using the scale rule on the main map page. You could calculate, here's how:- http://www.movable-type.co.uk/scripts/latlong.html . My opinion, the best solution would be to install Viking https://sourceforge.net/projects/viking/ It is free, it can display several OSM rederings, it as a print function ( well in windows, it does ) and there is a ruler tool that will measure point to point at any angle you want. answered 24 May '16, 21:50 andy mackey |
I don't really understand, sorry. Could you describe in other words? What is your goal? And: you mean the "image" feature in the share sidebar on https://www.openstreetmap.org , right?
I did a short calculation based on the scale you see at the bottom left corner: the scale which you can enter in the share dialogue seems to fit if you would print/view the exported image at 150 dpi.
I'm guessing that this refers to the "export" button at the top of the openstreetmap.org screen rather than the "arrow pointing out of a box" unlabelled button at the right, but yes - more words would help.
It's very likely that the best solution to the problem (whatever it is) is to not use the openstreetmap.org site itself, but one of the many other sites and tools that uses the same data.
I am sorry if that was not clear. I have updated the question. I hope now it is more understandable.