How can I match a key containing a colon in an OSMLib stylesheet?

Question

I was using the OSMLib osmexport function to produce KML maps of ski areas, when I discovered a problem. The oxr style file doesn't like tags with a semicolon in it it seems and it won't take the tag like this either: 'piste:downhill'

My style file is at: http://www.skimap.org/files/kml-openskimap.oxr And sample data at: http://www.skimap.org/data/28/osm/xml/2011-01-31.osm

Any suggestions? Thanks!

Accepted Answer

2

If the tag key is not a valid Ruby word, i.e. if it contains other characters than alpahnumerics and the underscore, you‘ll have to use the following syntax:

  # EDIT: changed "nodes do" to "ways do"
  ways do
    if tags['piste:type']
      ...
    end
  end

This is copy paste from osmlib rules documentation for exports, I use Osmium (also from Jochen) so I can't really tell you if you are doing stuff the right way, for the record osmium isn't at all suited for what you want to do.

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answered 01 Feb '11, 08:30

emj
2.0k●12●35●47
accept rate: 15%

edited 02 Feb '11, 09:32

But what if I want to select ways where piste:type=downhill? Your syntax only checks for the existence of the key, not the key value pair. Any idea how to do this?

(01 Feb '11, 23:11) wbski

1

I would guess you would do "tags['piste:type'] == 'emjpipe'" and I believe you have to iterate ways on their own just change nodes to ways in that code.

(02 Feb '11, 09:27) emj

How can I match a key containing a colon in an OSMLib stylesheet?

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