In the "my settings" section of my profile I can see whether I have already agreed to the new license terms (e.g. "You have agreed to the new Contributor Terms."). However, I could not find where I can check whether I have agreed also to the public domain status of my edits. Furthermore, I would like to know whether it is possible to change again (only) the public domain status. Regards |
If you have agreed to the public domain status, this will be displayed in "my settings": Contributor Terms: You have agreed to the new Contributor Terms. (what is this?) You have also declared that you consider your edits to be in the Public Domain. answered 26 Nov '10, 00:37 Richard ♦ |
You can use the API to check your status. Just visit http://api.openstreetmap.org/api/0.6/user/details answered 25 Nov '10, 09:54 aharvey Could you please explain more precisely what I have to do, because I just get some HTML code displayed.
(25 Nov '10, 12:39)
ALE
If this is under my settings you don't need to do it this way. That link would return an XML file which has the line like <contributor-terms agreed="false" pd="false"/>
(26 Nov '10, 11:05)
aharvey
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So there is actually no way to acceppt / retrieve public domain additional after registration? answered 13 Dec '10, 16:02 sgsi9000 Gnonthgol ♦ |
I was wondering whether it is possible to re-vote, since I made my choice without the necessary knowledge about public domain. answered 25 Jan '12, 14:37 Beeblebrox1900 2
By definition, you can't retract a public domain dedication. If you have placed your work in the public domain, you have given people permission to do whatever they want to do with it. You can't suddenly say "oh, I gave you it with no conditions, but now I'm imposing some conditions". However, you can of course create a new user account and use that instead. There doesn't appear to be a way to retroactively add the public domain permission (which would legally be possible). If you would like to see this feature, you could suggest it on our bug-tracking site, http//trac.openstreetmap.org/.
(25 Jan '12, 15:09)
Richard ♦
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